三角函数

sin20+sin40-sin80= ?
2025-12-25 06:32:25
推荐回答(1个)
回答1:

sin20+sin40-sin80
= 2sin[(40+20)/2]cos[(40-20)/2]-sin(90-10)
=2sin30cos10-cos10
=2(1/2)cos10-cos10
=cos10-cos10
=0